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Orbital Period

Explore orbital time, speed and the physics behind every revolution.

Orbital Inputs

5.972 × 10²⁴ kg

6,371 km

Height above the entered reference radius.

Advanced parameters

G = 6.67430 × 10⁻²⁰ km³ kg⁻¹ s⁻²

μ = G × mass = 398,600.4418 km³/s²

Mass equivalents use this G. Earth reference: μ = 398,600.4418 km³/s²; radius = 6,371 km.

Presets approximate spherical bodies. Atmospheric drag, oblateness, radiation pressure and third-body perturbations are omitted.

Calculation & assumptions

Circular orbit · Spherical central body · Negligible satellite mass

T = 2π √(R + h)³ / μv = √μ / (R + h)

R + h : Orbital radius = 6,771 km

μ : Gravitational parameter = 398,600.4418 km³/s²

T is the period; v is the constant circular-orbit speed. This is not an escape trajectory or a stability assessment.

Orbital Dynamics

ORBITAL PERIOD
92.4 minutes

1 h 32 min

Duration5,545 s
Orbital speed7.67 km/s
Orbits per day15.58
Illustrative circular orbit around EarthA satellite moves at a constant circular-orbit angular rate. The circle is viewed in perspective. Altitude is exaggerated for clarity; Earth texture is illustrative. EARTH · CIRCULAR ORBIT 400 km Illustrative perspective · Altitude exaggerated for clarity
One orbit: 92.4 min

Playback is accelerated 300×. It is a circular orbit shown in perspective.

How altitude changes an orbit

A higher altitude increases the orbital radius, which results in a longer orbital period and a lower orbital speed. Lower orbits complete more revolutions per day and have higher orbital speeds.

GEO~35,800 kmLEO~200–2,000 kmNot to scale

Worked example

Earth · 400 km altitude

r = 6,371 + 400 = 6,771 km

T ≈ 5,545 s ≈ 92.4 min

v ≈ 7.67 km/s

Using the mean Earth radius and conventional Earth gravitational parameter. Rounding is for display only.

Why orbital speed changes

An elliptical orbit, viewed from above. Gravity pulls more strongly near the central body.

Kepler’s second law: equal time, equal swept areaTwo shaded sectors have equal area and represent equal time intervals. The near arc is longer and faster; the far arc is shorter and slower. The central body lies at a focus, not the centre. NEAR · FASTERFAR · SLOWER Central bodyat one focus Same time Δt · Area ASame time Δt · Area A
Equal time → equal area. The shorter radius needs a longer arc to sweep the same area: the object moves faster.

Illustrative ellipse, not the circular orbit calculated above. On a circular orbit, speed stays constant.

Frequently asked questions

What is orbital period?

The orbital period is the time required for one complete revolution. Here the satellite is assumed to have negligible mass and to follow a circular orbit around a spherical central body.

Why does a higher orbit take longer?

A higher orbit has a longer path and a lower circular-orbit speed. In this model the period scales with orbital radius to the power 3/2.

Is the visualizer a live satellite tracker?

No. The scene is an illustrative, accelerated simulation driven by the entered values. It does not use live ephemerides, predict satellite locations, or establish whether a real orbit is safe or stable.

Does the ellipse in the teaching diagram change the calculation?

No. The separate Kepler diagram shows equal swept areas on an elliptical orbit. The calculator and main simulation remain circular; the apparent ellipse in the main scene is a perspective view of a circle.

What does this calculator estimate?

It estimates the time needed to complete one circular orbit.

Is this an exact mission-planning tool?

No. It is an educational calculator based on the stated constants and simplified assumptions.

How accurate is the result?

It assumes a two-body circular orbit and ignores perturbations, drag and oblateness.

Sources & References

References do not imply institutional endorsement. Preset radii: JPL planetary physical parameters and NASA mean-radius fact sheets.

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Explore orbital time, speed and the physics behind every revolution.

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Updated: October 7, 2026